hat do you think of when you see the numbers: 8200, 4600, 0060, 9189, and 31818? No, they are not a list of winning Indiana Lottery numbers. Rather, they are examples of guaranteed analysis values for the percentages of nitrogen (N), available phosphorus (P_{2}O_{5}) and watersoluble potassium (K_{2}O) in common fertilizer sources. These values represent plantavailable nutrients and are required by law to be publicly available when you purchase fertilizers in Indiana.
With these and so many other possible sources of fertilizer for use in Indiana row crop production, determining the least costly form of fertilizer can be challenging and unwieldy. When comparing potential sources of fertilizer, you ought to be calculating and comparing the relative costs per pound of nutrient, not the costs per ton of fertilizer product.
Unfortunately, fertilizer mathematics is not a strong suit for many agriculturalists. Sharpen your pencils and follow along with these examples of nutrient cost calculations. Remember, where appropriate, to substitute your own local fertilizer prices for those used in these examples.
For single nutrient fertilizer products such as anhydrous ammonia (8200) or 28% UAN (2800), calculating the costs per pound of nutrient is simple. Fertilizer sources and retail prices used for this example are anhydrous ammonia ($285/ton) and 28% UAN ($225/ton).
Example 1: Single Nutrient ProductsFirst, calculate the lbs of nutrient per ton of product:
Second, calculate the cost per lb of nitrogen:

This simple mathematical example also illustrates why anhydrous ammonia has historically been a popular source of fertilizer nitrogen for corn production in Indiana: It is typically a very inexpensive source of N.
Calculating the price per pound of nutrient for multiple analysis fertilizer products can be more challenging. Typically, the cost of one nutrient in the mix is of primary interest to you. Consequently, the costs for one or more of the other nutrient components of the mixture are set to standard values based on the cost of single nutrient sources.
For example, let’s say that you wanted to compare the relative nitrogen costs of 28% UAN (2800) and 10340 for making an economic decision on starter fertilizer products. Assuming that the phosphorus component of the 10340 is also of value to the crop, calculating the nitrogen cost share of the mix must therefore account for the cost share of the mix that can be attributed to the phosphorus.
Because the relative nitrogen costs are the ones of interest in this example, the phosphorus cost per lb P_{2}O_{5 }can simply be set to a standard value. What value should this be? The simplest value would be that equal to the price per lb of P_{2}O_{5 }in a common single nutrient source such as 0460 (triple super phosphate).
Fertilizer sources and retail prices used for this example are 28% UAN ($225/ton), 10340 ($260/ton), and 0460 ($260/ton).
Example 2a: Multiple Nutrient Products (N & P)First, calculate the lbs of nutrient per ton of product:
Second, calculate the standard cost per lb of P_{2}O_{5 }in 0460:
Third, calculate the phosphorus share of the total cost in one ton of 10340:
Fourth, calculate the nitrogen share of the total cost of 10340 per ton of product:
Finally, calculate the relative costs per lb of nitrogen for the two nitrogen sources:

This mathematical example indicates that the 10340 fertilizer product would be a less expensive source of nitrogen for use in starter fertilizer programs. The caveat to this, however, is the recognition that with 10340 you would be purchasing phosphorus in addition to nitrogen.
So, remember to finish this mathematical exercise by calculating the per acre cost for the two products. In order to do so, it is important that you calculate the per acre costs considering identical rates of starter nitrogen (apples to apples). Let’s assume a starter fertilizer nitrogen rate of 20 lbs N for both products:
Example 2b: Multiple Nutrient Products (N & P)First, calculate the per acre cost of the single nutrient 28% UAN product:
Second, calculate the per acre cost of the multiple nutrient 10340 product:

So, while 10340 is technically the cheaper source of nitrogen (per lb N) in this example, the total cost per acre would be greater than that for using 28% UAN as a starter fertilizer source because of the additional costs due to the phosphorus component of 10340. But hold on, the story does not end here.
IF the phosphorus component would be beneficial to the corn crop because of less than adequate phosphorus soil test levels, the additional cost per acre ($19) may be rewarded by increased corn yields. However, IF the phosphorus soil test levels were above the critical value for corn (greater than 30 lbs P per acre, Bray P_{1}), then the inclusion of the phosphorus in the starter mix may be of little value to the corn crop and, thus, the less expensive starter N source of 28% UAN would be the economic choice.
Calculating per pound costs for nutrients in products that contain nitrogen, phosphorus, AND potassium is slightly more challenging but similar to that described above for products containing two nutrients. Depending on which of the three nutrients is the one of interest, you simply set the price of the other two equal to that calculated from single nutrient sources. For example, if you wanted to calculate the nitrogen cost of a multiple analysis product such as 9189, you would first subtract the relative costs of the phosphorus and potassium portions from the total cost.
Assume you wanted to calculate the nitrogen share of the cost of a 9189 liquid fertilizer. The phosphorus and potassium share of the fertilizer product cost will be calculated using standard costs per lb for P_{2}O_{5 }and_{ }K_{2}O,_{ }calculated_{ }from the single nutrient sources 0460 and 0060.
This example also illustrates how to calculate nutrient price per pound when the product is priced on a per gallon basis, not on a per ton basis. Fertilizer sources and retail prices used for this example are the common single nutrient sources 0460 ($260/ton), 0060 ($175/ton), and 9189 ($3/gallon).
Example 3: Multiple Nutrient Solution Products (N, P, & K)First, calculate the standard cost per lb of P_{2}O_{5 }and K_{2}O:
Second, calculate the lbs per gallon of 9189 for the nitrogen, phosphorus, and potassium nutrient components of this fertilizer product. This product, like many fertilizer solutions, weighs about 11 lbs per gallon.
Third, calculate the relative cost shares of P_{2}O_{5 }and K_{2}O in one gallon of 9189:
Finally, calculate the cost per lb of nitrogen in 9189:

Surprised? Many liquid fertilizer products sold on a per gallon basis can be quite expensive on a per pound of nutrient basis, yet are no more effective or efficient in supplying nutrients to crop plants. This fact alone makes it worth your while to become skilled at fertilizer mathematics.
These examples provide you with some guidelines to follow in order to calculate nutrient costs on a per pound basis. Working with single nutrient sources is simple and straightforward. Working with multiple nutrient sources is somewhat more complicated, yet also fairly straightforward if you follow the steps.
Remember that most fertilizer products are equally effective in their use as crop plant nutrient sources. Part of your decision process for fertilizer inputs involves calculating and comparing the relative costs among alternative products. Taking the time to do the type of fertilizer reckoning described in this article will better enable you to compare the relative costs of different fertilizer products.